A ball of mass m kg moving at u m/s hits a smooth horizontal plane at an angle of x to the horizontal. The coefficient of restitution is 0.
Find the impulse on the plane.
Here is what I did:
Since e=0, there is no vertical velocity, so the speed after=horizontal speed before.
I = m(v - u)
so I = m(u cos x + u) = mu(cos x +1)
however the answer in the book gives something else.
Where have I gone wrong?
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- Thread Starter
- 09-11-2016 18:48
- 09-11-2016 19:44
Does the book give ?
If so you need to draw the diagram with the components of velocity parallel and perpendicular to the plane. The velocity parallel to the plane will not change.Last edited by Cryptokyo; 09-11-2016 at 19:46.