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# Can someone please have a look at this maths question? (C1) watch

1. The triangle with vertices (0,0) (1,p), (10,0) is right angled. Find the two possible values of p.

2. (Original post by honour)
The triangle with vertices (0,0) (1,p), (10,0) is right angled. Find the two possible values of p.

Plot (0,0), (10,0) and draw the line x = 1 and work from there
3. firstly draw sketch. always helps . hint product of perpendicular gradients = -1
4. It's right-angled. So it satisfies Pythagoras's theorem. Can you apply this here? You should end up with a quadratic in .
5. (Original post by Chemgawd99)
firstly draw sketch. always helps . hint product of perpendicular gradients = -1
But the gradient of the line passing through (0,0) and (10,0) is 0... what multiplies 0 to get -1?
6. (Original post by honour)
But the gradient of the line passing through (0,0) and (10,0) is 0... what multiplies 0 to get -1?
sketch the triangle and you will see line passing through (0,0) (1,p) and line passing through (1,p) (10,0)
7. the answer is p=3 and p=-3
8. i will post the working one min
9. (Original post by perks23)
x
Thank you ever so much! Your presentation is so neat!

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