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    Can anyone help me with this question?

    25.0cm3 of 0.100moldm-3 HCl is put into a conical flask. Indicator is added. The acid is titrated against NaOH solution of unknown concentration. 17.9cm3 of alkali neutralises the acid.

    How many moles of alkali were added to neutralise the acid?
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    (Original post by Tayla1998)
    Can anyone help me with this question?

    25.0cm3 of 0.100moldm-3 HCl is put into a conical flask. Indicator is added. The acid is titrated against NaOH solution of unknown concentration. 17.9cm3 of alkali neutralises the acid.

    How many moles of alkali were added to neutralise the acid?
    1) write balanced chemical equation between HCl and NaOH
    HCl + NaOH --> NaCl + H2O

    2) mole of HCl/mole of NaOH = 1/1 (from balanced equation)
    so mole of NaOH = mole of HCl

    3) know that for solutions, concentration in mol per dm3 multiplied by volume of solution in dm3 gives you mole.

    so...you continue.
 
 
 
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