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    A block of mass 2kg is on a smooth slope of 30 degrees. If it slides from rest at X, find its speed at Y after moving 10m down the slope...

    Answer is 10ms-1

    Draw a triangle of forces on the object and begin to resolve the vectors.


    You can resolve the downward force on the slope as 2gN, hence the force parallel to the slope is 2g\cos 30N. Hence F=16.99N to 4 s.f.

    Since F=16.99N parallel to the slope, \Rightarrow a_{parallel} = \frac{F}{m} = \frac{16.99}{2} = 8.496m/s2 to 4 s.f. Thus, using the SUVAT equation v^2 = u^2 + 2as:

    v^2 = u^2 + 2as\\ \Rightarrow v^2 = 0^2 + 2 \times 8.496 \times 10 = 169.9 \Rightarrow v = 13.035 which is 10m/s to 1 s.f. (as 1 s.f. is the lowest given in the question).

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