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    Can someone please give me some pointers as to go about solving the following

    A eats twice as fast as B.

    A and B together eat 2400 apples in 4 hours.

    A, B and C together eat 3600 apples in 3 hours.

    How many apples can C eat in 4 hours and 27 minutes?


    A and B eat 2400 in 4 hours BUT B is twice as fast as A, meaning in 1 hour, A eats 400 and B eats 200.

    So in 3 hours, they eat 1200 + 600 = 1800.

    We know A, B and C together eat 3600 in 3 hours, so C alone eats 1800 in 3 hours, ie 600 per hour.

    Therefore in 4 hours and 27 mins, ie 4+(27/60) hours, C eats (4+27/60) * 600 = 2670 apples.

    Seems all correct.
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