Join TSR now and get all your revision questions answeredSign up now

Ratio question

    • Thread Starter

    Can someone please give me some pointers as to go about solving the following

    A eats twice as fast as B.

    A and B together eat 2400 apples in 4 hours.

    A, B and C together eat 3600 apples in 3 hours.

    How many apples can C eat in 4 hours and 27 minutes?


    A and B eat 2400 in 4 hours BUT B is twice as fast as A, meaning in 1 hour, A eats 400 and B eats 200.

    So in 3 hours, they eat 1200 + 600 = 1800.

    We know A, B and C together eat 3600 in 3 hours, so C alone eats 1800 in 3 hours, ie 600 per hour.

    Therefore in 4 hours and 27 mins, ie 4+(27/60) hours, C eats (4+27/60) * 600 = 2670 apples.

    Seems all correct.
Which party will you be voting for in the General Election 2017?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Quick reply
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.