# how would you differentiate

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#1
16x+4y-19=0?
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#2
?????
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3 years ago
#3
16x+4y-19=0
differentiated is 16+4dy/dx+0

dy/dx=-16/4
Dy/dx=-4
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3 years ago
#4
If you've been asked to differentiate with respect to , first rearrange so to that you get an equation starting with .

Then, differentiate as normal.
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3 years ago
#5
(Original post by p29)
16x+4y-19=0?
Like the above said

rearrange for y

4y=19-16x
y=19/4 -4x

then differentiate and you've got an answer
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3 years ago
#6
You have two options.

Differentiating dy by dx means with respect to x, in terms of y. However your equation has a term with respect to y inside.

So the 'simple' solution is to re-arange for y.
16x+4y-19=0
y = 1/4(19-16x)

dy/dx = -4

now you have an equation in terms of y with respect to x. Which you can differentiate dy by dx.

Otherwise (depending on if you've learned), you can differentiate implicitly, this isn't so much of an issue for your equation as it can be re-arrange fairly simply. However for equations that are a lot more complex, implicitly is the way to go.

d [16x+4y-19] by dx
16 + 4 dy/dx = 0
4 dy/dz = -16
dy/dx = -4

so you now have the differential of -4
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