# Calculus Taylor Theorem approximation helpWatch

#1
I'm stuck on a certain part of the lecture notes here:

I don't understand how the +x^5cos^5(c) changed into -x^5sin(c) when i was simplified, is there something I am missing?
0
2 years ago
#2
(Original post by Sayless)
I'm stuck on a certain part of the lecture notes here:

I don't understand how the +x^5cos^5(c) changed into -x^5sin(c) when i was simplified, is there something I am missing?
The notation refers to the fifth derivative of evaluated at , not the fifth power. The fifth derivative of is precisely .
1
#3
(Original post by Zacken)
The notation refers to the fifth derivative of evaluated at , not the fifth power. The fifth derivative of is precisely .
ahhhhhhhhhhhhhhh, thanks that makes sense now
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