Calculus Taylor Theorem approximation help Watch

Sayless
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I'm stuck on a certain part of the lecture notes here:

I don't understand how the +x^5cos^5(c) changed into -x^5sin(c) when i was simplified, is there something I am missing?
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Zacken
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(Original post by Sayless)
I'm stuck on a certain part of the lecture notes here:

I don't understand how the +x^5cos^5(c) changed into -x^5sin(c) when i was simplified, is there something I am missing?
The notation \cos^{(5)} c refers to the fifth derivative of \cos evaluated at c, not the fifth power. The fifth derivative of \cos is precisely -\sin.
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Sayless
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(Original post by Zacken)
The notation \cos^{(5)} c refers to the fifth derivative of \cos evaluated at c, not the fifth power. The fifth derivative of \cos is precisely -\sin.
ahhhhhhhhhhhhhhh, thanks that makes sense now
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