titrations-a level chemistry Watch

elfstudent
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0.0400g of NaOH was dissolved in water, making 25.00cm3 NaOH solution. 23.50cm3 of this solution is used to neutralise 15.00cm3 H2SO4 what is concentration of H2S04
2NaOH+H2SO4---Na2SO4+2H2O
please can someone help me with this!? I’m so confused because there is no moles stated
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L.D.S.
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Don't quote me on this but I think you use either n=VxC/1000 or C1V1=C2V2

(Original post by elfstudent)
0.0400g of NaOH was dissolved in water, making 25.00cm3 NaOH solution. 23.50cm3 of this solution is used to neutralise 15.00cm3 H2SO4 what is concentration of H2S04
2NaOH+H2SO4---Na2SO4+2H2O
please can someone help me with this!? I’m so confused because there is no moles stated
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elfstudent
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(Original post by LDS16)
Don't quote me on this but I think you use either n=VxC/1000 or C1V1=C2V2
okay, ill try and use the first equation and see what i get
thank you!
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username2752874
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(Original post by elfstudent)
0.0400g of NaOH was dissolved in water, making 25.00cm3 NaOH solution. 23.50cm3 of this solution is used to neutralise 15.00cm3 H2SO4 what is concentration of H2S04
2NaOH+H2SO4---Na2SO4+2H2O
please can someone help me with this!? I’m so confused because there is no moles stated
1. Find the moles of NaOH. Use number of moles = mass/molar mass
2. Use molar ratios to find the number of moles of H2SO4
3. Use Concentration = number of moles divided by volume in dm3.

To get dm3 from cm3, you divide by a 1000.

You should get a concentration of 0.0333 mol dm-3
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niv1234
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(Original post by elfstudent)
0.0400g of NaOH was dissolved in water, making 25.00cm3 NaOH solution. 23.50cm3 of this solution is used to neutralise 15.00cm3 H2SO4 what is concentration of H2S04
2NaOH+H2SO4---Na2SO4+2H2O
please can someone help me with this!? I’m so confused because there is no moles stated
I think you can work out the moles from the equation moles = concentration times volume. Remember to convert the volume into dm^3 first though.

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I just did this in year 12 chemistry in school today - how convenient.
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