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Trigonometry!

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    Can someone help me? I can't remember how to handle the part in the brackets here:

    Sec(3x+ Pi/6 )= -2/(3^1/2)
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    (Original post by Carokelly123)
    Can someone help me? I can't remember how to handle the part in the brackets here:

    Sec(3x+ Pi/6 )= -2/(3^1/2)
    1) Take your equation and write it in terms of cosine
    2) Whatever your range for x is, find the corresponding range for 3x + pi/6
    3) Find the values that satisfy 3x+pi/6 for the range
    4) Find x
 
 
 
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Updated: November 14, 2016
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