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# How to calculate the depth of a spread of a given volume watch

1. If I have a volume of water that is 54,000km3, and I pour it into a container that has an area of 361,330,000km2 (and as high as it needed to be), how high would the water come up the container? (and/or how is this calculated?

Thanks
2. (Original post by Farchitect)
If I have a volume of water that is 54,000km3, and I pour it into a container that has an area of 361,330,00km2 (and as high as it needed to be), how high would the water come up the container? (and/or how is this calculated?

Thanks
Volume / Area, i.e. 54000 divided by 361330000 (I don't know whether you missed off a zero in the end there, or misplaced the comma).
3. The key hear is that the volume is conserved and so area X height = 54000 which ends up with about 150mm (using 54000 and 361,330,000)

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