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Hey, i was just wondering how pople would deal with arccosecx?

Arccosecx = arc(1\sinx) = 1/arcsinx

or = (1/sinx)^-1 = sinx

in th p2 book it asked me to draw the graph of y=arccosecx an igot kinda confussed. if anyone could clear this up for me that would be great.

Arccosecx = arc(1\sinx) = 1/arcsinx

or = (1/sinx)^-1 = sinx

in th p2 book it asked me to draw the graph of y=arccosecx an igot kinda confussed. if anyone could clear this up for me that would be great.

wait a minute, just thought, are those two possible answers i gave the same?

Thanx

Umm I could be wrong, but don't you draw y=cosec(x) and reflect into the line y=x? It's got a limited domain as well, otherwise it's not a one-one function.

Hey, i take ur word for it, but how did u come to that answer?

kingmonkeywoman

Hey, i take ur word for it, but how did u come to that answer?

y = arcsinx

=> siny = x

=> cosecy = 1/x

=> y = arcosec(1/x)

therefore arcsinx = arcosec(1/x) or arcosec(t) = arcsin(1/t) [t]

Thanx , cant say i would have approached it like that myself, nice one

integral_neo

Did you manage to download all the papers coz im takin them down soon?

Yeah I have all the papers thanks for putting them up

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