ok just a few things i need help with.
integration, denote to c
3x^-1= 3in(x) + c or in(3x) + c ??
x^-2= i can do this if it is x^-1 and x^-3, etc. just not 2, unless its 1/1x^-1 which surely cant be right?
3/2 exp (3x) = how do you integrate if its a fraction? as in 3 over 2?
erm check if i done this rght: 3 S (x^3 + x^2 +x) = 3 1/4x^4 + 1/3x^3 + x^2/2 + c ?? im worried about how you place the 3 into the answer have i done it right or do you need to do something else.
Also could someone work through this example: that way i know how to use the quotient rule for differentiation!!
x^2 + 2x + 4
will appreciate the help people!!
Turn on thread page Beta
A few quick questions, Plz help watch
- Thread Starter
- 27-08-2007 15:16
Offline14ReputationRep:Wiki Support Team
- Wiki Support Team
- 27-08-2007 15:23
Well, 3x^-1 means 3 . (x^-1), so it integrates to 3 ln x + c.
The integral of x^-2 is (x^-1)/-1 = -x^-1 = -1/x.
3/2 is just a constant. Treat it like you'd treat, say, the 4 in: 4 exp 3x.
Your next integral - there should be a bracket round everything, so 3 (1/4x^4 + 1/3x^3 + x^2/2) + c. (Another acceptable answer would be 3 (1/4x^4 + 1/3x^3 + x^2/2 + c) - the 'c' is different in both cases, but that doesn't make any difference.)
Quotient rule... .
So in your example:
which you can then simplify.
Phew, long post, hope I didn't make any slips.