Original post by muf_mur
Please help me I can't seem to make head or tail of this.
Prove that the moment of inertia of a uniform rod of length 2a about an axis intersecting the rod at right angles at a distance b from its center is m(1/3 a2 +b2), where m is the mass of the rod.
Prove that the moment of inertia of a uniform rod of length 2a about an axis intersecting the rod at right angles at a distance b from its center is m(1/3 a2 +b2), where m is the mass of the rod.
Draw a diagram of the problem i.e. a horizontal rod with length 2a. Where is its centre of gravity? Where is the b-axis?
Calculate the moment of inertia about the centre of gravity:
I've omitted the limits to give you something to think about.
Use the parallel axis theorem to determine the moment of inertia about the b-axis.
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