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    x4+3x2+2

    When you integrate this, wouldn't you get: x^5/5 + x^3/3 + 2x?
    According to the mark scheme the bit in red is supposed to be 3x^3/3. Does anyone know why that is, because I have no idea. Thanks.

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    (Original post by u.sha)
    x4+3x2+2

    When you integrate this, wouldn't you get: x^5/5 + x^3/3 + 2x?
    According to the mark scheme the bit in red is supposed to be 3x^3/3. Does anyone know why that is, because I have no idea. Thanks.
    \int x^2 \ dx = \frac{x^3}{3}

    Hence,

    \int 3x^2 \ dx = \frac{3x^3}{3}
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    (Original post by u.sha)
    x4+3x2+2

    When you integrate this, wouldn't you get: x^5/5 + x^3/3 + 2x?
    According to the mark scheme the bit in red is supposed to be 3x^3/3. Does anyone know why that is, because I have no idea. Thanks.
    For integrating 3x^2
    add one to the power and divide by the new power.

    so 3x^3 /3

    (you just forgot to include the coefficient of x squared)
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    (Original post by u.sha)
    x4+3x2+2

    When you integrate this, wouldn't you get: x^5/5 + x^3/3 + 2x?
    According to the mark scheme the bit in red is supposed to be 3x^3/3. Does anyone know why that is, because I have no idea. Thanks.
    Add one more, drop it though the trapdoor.

    And don't forget the constant of integration.
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    (Original post by SherlockHolmes)
    \int x^2 \ dx = \frac{x^3}{3}

    Hence,

    \int 3x^2 \ dx = \frac{3x^3}{3}
    (Original post by bobwibbles)
    For integrating 3x^2
    add one to the power and divide by the new power.

    so 3x^3 /3

    (you just forgot to include the coefficient of x squared)
    (Original post by Mr M)
    Add one more, drop it though the trapdoor.

    And don't forget the constant of integration.
    ohhhhh i see where i went wrong. oh myyy :eek4:
    whoops
    thanks!!
 
 
 
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