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    Attachment 608138hello

    HOW THE HELL DID THEY GET CO-ORDINATE B as (7,0)??????
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    (Original post by CorpusLuteum)
    Attachment 608138hello

    HOW THE HELL DID THEY GET CO-ORDINATE B as (7,0)??????
    Attachment not found, perhaps type the question in or provide a link to it online?
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    the attachment doesnt work
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    Name:  Screen Shot 2017-01-03 at 19.38.55.png
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    (Original post by Maz A)
    Attachment not found, perhaps type the question in or provide a link to it online?
    (Original post by gaary kasparov)
    the attachment doesnt work
    it worked above now right
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    not done that in edexcel c1. we only just started c2 so cant help you. sorry.
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    (Original post by CorpusLuteum)
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    ez question lel

    well you're gonna make an isoceles triangle aren't you? with lines CA and CB equalling each other, in other words CA=CB
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    (Original post by will'o'wisp)
    ez question lel

    well you're gonna make an isoceles triangle aren't you? With lines ca and cb equalling each other, in other words ca=cb
    but its one mark?
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    (Original post by CorpusLuteum)
    it worked above now right
    ABC is an equilateral triangle, so the length of AC = CB. Difference in x coordinates from A to C is 3 (4-1) so the difference in x coordinates between C and B will be the same, so it's 4+3=7.
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    (Original post by CorpusLuteum)
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    Find the radius length from the distance between A and C, use that to find the equation of the circle and then equate to the x axis and solve
    Or, what's probably easier is looking at how A and B are equidistant from C. In the x axis, A is 3 from C. B must be 3 from C, and 4 (the centre x coordinate) +3 is 7
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    (Original post by CorpusLuteum)
    but its one mark?
    mmhm

    That's what you should be thinking.

    No matter how you place the circle the distance from the centre of the circle to the points where the circle touches the x-axis will be exactly the same length.

    When you realise this you can see the difference in x-values for C and A 4-1=3 so 3 is the difference between the x-coord of the centre and the first point where the circle touches the x-axis. The distance will therefore be the same from the x-coord of the centre to B


    In other words CA=CB

    I'm sure there's a circle theorem which says if you draw a chord and draw 2 lines from either end of the chord to the centre of the circle then you get isosceles triangle.

    With a little bit of thinking it's the 3rd picture on the left from top to bottom
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    I think because point C is in the centre of the circle, you know that points A and B are of equal distances from C. You already know the y coordinate which is 0 and you find out the x coordinate by finding the difference between the x coordinate of A and C and adding it on to 4 which is 7. If I'm correct, the answer will be (7, 0)
 
 
 
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