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    How did they do part iv

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    (Original post by CorpusLuteum)
    How did they do part iv

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    which year is it ?
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    (Original post by h3rmit)
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    I attached it again
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    (Original post by mgy2000)
    which year is it ?
    2014 june OCR MEI
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    First find the coordinates for d. Then use y-y1=m(x-x1) by subbing in A and D's coordinates and then you can find m. Then sub in m and d coordinates into y=mx+c and find c. Final form will be y= (your m)x+(Your c)
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    work out the gradient of bc
    flip the fraction and put a negative as ad is the negative reciprocal of bc , this will give u gradient of ad
    y-y1=m(x-x1) where m is gradient and sub the coordinates of c and there u hv it
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    (Original post by CorpusLuteum)
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    Find the gradient of the line AD and call this m. Then the gradient of the tangent line at D is the negative reciprocal of m.
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    (Original post by CorpusLuteum)
    I attached it again
    Find the gradient of AC or AD or DC, and use that in y=mx+c
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    (Original post by h3rmit)
    Find the gradient of AC or AD or DC, and use that in y=mx+c
    but why?
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    (Original post by CorpusLuteum)
    but why?
    So you can pass your maths exams, get into a good uni, get a good job and be prepared for life? I'm not really sure what justifcation you're looking for
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    I do OCR without the MEI so idk if you would do it the same way as me but I hope this helps


    Find the gradient of the line AD as this will be perpendicular to the tangent that you need to find.
    (4-0)/(7-1) = 2/3
    The gradient of the tangent will be the negative reciprocal of this. (Because they are perpendicular to each other)
    -3/2
    Put this gradient into a straight line equation
    y=mx+c
    y=-3/2x+c
    Substitute your x and y for D in to work out c
    4=-3/2(7) + c
    c=14.5

    So y=(-3/2)x+14.5
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    Work out the gradient of AD. The gradient of the tangent at D is the negative reciprocal of this since you know that a tangent is perpendicular to a diameter (or radius). From there you should be able to work out the equation of the line
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    (Original post by h3rmit)
    So you can pass your maths exams, get into a good uni, get a good job and be prepared for life? I'm not really sure what justifcation you're looking for
    lol, i meant why find the gradient of AC isn't a tangent perpendicular to it?
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    (Original post by CorpusLuteum)
    lol, i meant why find the gradient of AC isn't a tangent perpendicular to it?
    Yes
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    (Original post by klm7)
    I do OCR without the MEI so idk if you would do it the same way as me but I hope this helps


    Find the gradient of the line AD as this will be perpendicular to the tangent that you need to find.
    (4-0)/(7-1) = 2/3
    The gradient of the tangent will be the negative reciprocal of this. (Because they are perpendicular to each other)
    -3/2
    Put this gradient into a straight line equation
    y=mx+c
    y=-3/2x+c
    Substitute your x and y for D in to work out c
    4=-3/2(7) + c
    c=14.5

    So y=(-3/2)x+14.5
    tenks i get it
 
 
 
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