Can someone help me with this question:
So stress= force/cross-sectional area
We are given the stress?
We want the force
I need to work out the cross-sectional area.
Is that pi*(15mm-0.7mm)^2?
Also I don't get what is meant by a factor of safety of 3.
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Tensile strength/ force question help watch
- Thread Starter
- 04-01-2017 18:05
- 04-01-2017 20:27