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    Using mass spectra, calculate the Ar of the following element:
    Given that lead has four isotopes, 204Pb with an abundance of 23.6%. 206Pb with an abundance of 23.6%, 207Pb with an abundance of 22.6% and 208Pb with an abundance of 52.3%.

    Isotopic mass and Relative abundance (percentage)
    204.0 = 1.55%
    206.0 = 23.6%
    207.0 = 22.6%
    208.0 = 52.3%

    Ar = ?
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    do (204 x 23.6) + (206 x 23.6) +(207 x 22.6) + (208 x 52.3) / 100
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    (Original post by khxtijah)
    do (204 x 23.6) + (206 x 23.6) +(207 x 22.6) + (208 x 52.3) / 100
    Makes sense now. Thanks for your help
 
 
 
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