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    Hi All
    Attached below is a question from OCR's A2 (new spec) specimen paper. I've attached the question and my current workings. I can't get to their answer whatsoever, I'm way out in terms of order of magnitude, any insight would be greatly appreciated.
    Thanks
    James
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    attachment failed.

    presuming you're after the work done getting between two altitudes

    Id work out the potential energy at both altitudes and the difference is the work done in getting between them.
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    (Original post by james0902)
    Hi All
    Attached below is a question from OCR's A2 (new spec) specimen paper. I've attached the question and my current workings. I can't get to their answer whatsoever, I'm way out in terms of order of magnitude, any insight would be greatly appreciated.
    Thanks
    James

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    Which paper is it exactly? Could you post a link to the paper?
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    (Original post by james0902)
    Hi All
    Attached below is a question from OCR's A2 (new spec) specimen paper. I've attached the question and my current workings. I can't get to their answer whatsoever, I'm way out in terms of order of magnitude, any insight would be greatly appreciated.
    Thanks
    James
    Attachment 609244
    Name:  ImageUploadedByStudent Room1483806933.495105.jpg
Views: 39
Size:  57.3 KB


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    You cannot can simply use Force times distance travelled parallel to the direction of the force. Because gravitational force is not constant and you cannot find the so called average force without using calculus.

    Try the method proposed by joinedup.
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    (Original post by Eimmanuel)
    You cannot can simply use Force times distance travelled parallel to the direction of the force. Because gravitational force is not constant and you cannot find the so called average force without using calculus.

    Try the method proposed by joinedup.
    How would you go about working out the potential energies at these altitudes though?


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    (Original post by james0902)
    How would you go about working out the potential energies at these altitudes though?


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    Potential energy for the system is -GMm/r, where r is the sum of earth radius and altitude.
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    (Original post by james0902)
    How would you go about working out the potential energies at these altitudes though?


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    (Original post by Eimmanuel)
    Potential energy for the system is -GMm/r, where r is the sum of earth radius and altitude.
    It's given in the new OCR data & formula sheet (I checked earlier)
    http://www.ocr.org.uk/Images/302734-...ps-booklet.pdf
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    (Original post by james0902)
    How would you go about working out the potential energies at these altitudes though?


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    You may also want to post the question as well, just in case I misinterpret what is required.
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    (Original post by Eimmanuel)
    You may also want to post the question as well, just in case I misinterpret what is required.
    Name:  ImageUploadedByStudent Room1483875668.552120.jpg
Views: 23
Size:  114.4 KB

    That's the question, has it posted this time?


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    (Original post by james0902)
    Name:  ImageUploadedByStudent Room1483875668.552120.jpg
Views: 23
Size:  114.4 KB

    That's the question, has it posted this time?


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    It is posted this time. I think the power of 10 in the choices are not given in the correct power - the correct power should be  10^9 .

    Check with your school teacher to see if they have the updated or corrected version.
 
 
 
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