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    Question : Integrate \frac{1}{3\sqrt{y}} with respect to y.
    I added 1 to \frac{-1}{3} to get \frac{2}{3} as the power of y.
    Then divided y by \frac{2}{3} to get the answer:
    \frac{3}{2} y to the power of \frac{2}{3}

    But the mark scheme says the answer is \frac{2}{3}y to the power of \frac{1}{2} . I'm not sure how they got this answer. Can someone explain please?
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    I think you have read the question incorrectly. I don't think that the 3 means "the cube root of y". I think it means one over three times the square root of y.
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    (Original post by Chelsea12345)
    Question : Integrate \frac{1}{3\sqrt{y}} with respect to y.[/latex]
    Nice LaTex!

    \displaystyle \int \frac{1}{3\sqrt{y}} \, dy = \int \frac{y^{- \frac{1}{2}}}{3} \, dy

    Does that help? You may need to revise fractional and negative indices before proceeding with this topic.
 
 
 
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