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    How to prove a point is the origin?ii
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    (Original post by CorpusLuteum)
    How to prove a point is the origin?ii
    I'm assuming it's part A??

    Just get it in the form (x-a)^2+(y-b)^2=c^2 and show that a=4 and b=2
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    (Original post by RDKGames)
    I'm assuming it's part A??

    Just get it in the form (x-a)^2+(y-b)^2=c^2 and show that a=4 and b=2
    It's part 2; I've already worked out the radius=square root 29 but it says show that (4,2) is the origin inside the circle
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    (Original post by CorpusLuteum)
    It's part 2; I've already worked out the radius=square root 29 but it says show that (4,2) is the origin inside the circle
    If any point is inside a circle then the distance between that point and the origin of the circle must be less than the radius.
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    Make one zero to remove a term (à or b) then do the other one. By substituting in values of a or b that cancel out in the circle.
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    (Original post by RDKGames)
    If any point is inside a circle then the distance between that point and the origin of the circle must be less than the radius.
    How would you show that though?
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    (Original post by CorpusLuteum)
    How would you show that though?
    I just told you. Show that the distance between the origin and the centre of the circle is less than the radius by doing some Pythagoras - though you can skip the set up if you can notice that the form (x-4)^2+(y-2)^2 is essentially Pythagoras's for distance between a point (x,y) and (4,2), so just plug (0,0) into that and square root it. It should less than the radius.
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    mmm...looks a bit challenging...but will find a way :P
    (Original post by CorpusLuteum)
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