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    100 mL 0.1 M sodium acetate solution is mixed with 50 mL 0.1 M acetic acid. If now 0.914 mL of 1 M sodium hydroxide is added to the buffer what is the change in pH? pKa (acetic acid) = 4.76.
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    (Original post by tasnzari09)
    100 mL 0.1 M sodium acetate solution is mixed with 50 mL 0.1 M acetic acid. If now 0.914 mL of 1 M sodium hydroxide is added to the buffer what is the change in pH? pKa (acetic acid) = 4.76.
    You need to work out the pH before and the pH, subtract and that's the 'change in pH'.

    Remember that its the pKa value, therefore you have to use the equation:

    pH = pKa - log ([HA] / [A-])

    Where HA is the acetic acid and A- is the OH- ion

    CheeseIsVeg this is right, right? :lol:
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    (Original post by titfortat)
    You need to work out the pH before and the pH, subtract and that's the 'change in pH'.

    Remember that its the pKa value, therefore you have to use the equation:

    pH = pKa - log ([HA] / [A-])

    Where HA is the acetic acid and A- is the OH- ion

    CheeseIsVeg this is right, right? :lol:
    Haven't done this yet so :dontknow:
    Doing electrode potentials m9 :cool:
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    (Original post by CheeseIsVeg)
    Haven't done this yet so :dontknow:
    Doing electrode potentials m9 :cool:
    Ahh well nvm then :rofl:

    Thats the topic I hate the most in physical chem lmao XD
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    (Original post by titfortat)
    Ahh well nvm then :rofl:

    Thats the topic I hate the most in physical chem lmao XD
    I love physical chem :fan: can't wait now lol
 
 
 
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