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Differentiation

Chelsea12345

Find y dx when
y= 3x^2 - x +6

This was on integration question paper so do i differentiate this?

(edited 7 years ago)

Reply 1

Mr M

Study Forum Helper

Original post by Chelsea12345

To differentiate, do you take multiply by the power first then take 1 away from the power or do you take 1 from the power then multiply by the power?

The former.

Reply 2

NotNotBatman

\frac{d}{dx} (ax^n) = anx^{n-1}

That is multiply by the original power, then reduce the power by 1.

Reply 3

crashMATHS

Original post by Chelsea12345

To differentiate, do you take multiply by the power first then take 1 away from the power or do you take 1 from the power then multiply by the power?

Multiply then take away. In other terms,

\frac{d}{dx} [x^n] = nx ^{n-1}

, where n is a constant.

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Reply 4

FrenchNerd2

Original post by Chelsea12345

To differentiate, do you take multiply by the power first then take 1 away from the power or do you take 1 from the power then multiply by the power?

the order doesn't matter, at least for simple differentiation:

y=ax^n => dy/dx = nax^(n-1)

Reply 5

Mr M

Study Forum Helper

Original post by Chelsea12345

Find y dx when
y= 3x^2 - x +6

This was on integration question paper so do i differentiate this?

No you need to integrate. Please don't change your questions like this. It makes the thread impossible to follow.

Reply 6

Chelsea12345

Original post by Mr M

No you need to integrate. Please don't change your questions like this. It makes the thread impossible to follow.

Apologies! And why integrate? Aren't you finding what the equation is after it has been differentiated since integration is the opposite of differentiation? I'm a bit confused on this.

Reply 7

Mr M

Study Forum Helper

Original post by Chelsea12345

Apologies! And why integrate? Aren't you finding what the equation is after it has been differentiated since integration is the opposite of differentiation? I'm a bit confused on this.