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    My little sister needs help with this question:

    Two discs each with a number on both of their faces are tossed into the air. The two numbers that can be seen when the discs land are added to get a total. This is repeated three more times, and the totals obtained were 5, 11, 19, 25. Two of the original numbers were bigger than 10. What four numbers are written on the faces of the discs?

    ok, so if you work logically, it is aparrent that to get 5, the only possible combinations are 4+1, or 2+3. these will thus account for the two numbers below 10. Then, moving on to 11, the only combination of numbers utilising one of these 4, while allowing the second number to be 10 or greater is 1 and 10. So we have 1,4, 10 so far. the final number must then be 15, as 4 + 15 is 19. so, 1,4,15,10
    Hope this helps
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Updated: January 7, 2017
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