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    How would I get the monomer from this polymer (which I think is formed by condensation polymerisation):
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    Thank you
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    (Original post by jamesthelam)
    How would I get the monomer from this polymer (which I think is formed by condensation polymerisation):
    Name:  IMG_20170108_112403.jpg
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    Thank you
    Because the polymer is basically repeating units of a monomer, I'm pretty sure you can take two carbons from that polymer and add a double bond in the middle, and the CH3 branches are the repeating units.
    If the side groups were different, then you would choose the two carbons which when repeated would give you the pattern in the question.
    I don't think I explained it very well so attached a picture haha.
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    (Original post by lemonlikelime)
    Because the polymer is basically repeating units of a monomer, I'm pretty sure you can take two carbons from that polymer and add a double bond in the middle, and the CH3 branches are the repeating units.
    If the side groups were different, then you would choose the two carbons which when repeated would give you the pattern in the question.
    I don't think I explained it very well so attached a picture haha.
    Thank you! I was thinking that since there were four carbons in the brackets there must have been something more complicated going on but maybe they just did that to confuse people
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    If you wanted, you could use 1,1,2,2,3,3,4,4-octamethylcyclobutane.

    I expect the yield would be rather low, though.
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    (Original post by jamesthelam)
    Thank you! I was thinking that since there were four carbons in the brackets there must have been something more complicated going on but maybe they just did that to confuse people
    ahah I really hope it isn't - it's unlikely tbh, how many marks was it?
    sorry if im wrong!
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    (Original post by lemonlikelime)
    ahah I really hope it isn't - it's unlikely tbh, how many marks was it?
    sorry if im wrong!
    I don't know, this is a homework booklet without marks on the questions, so no guidance from that.
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    For the record, the answer they're looking for is indeed 2,3-dimethylbut-2-ene.
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    (Original post by Pigster)
    For the record, the answer they're looking for is indeed 2,3-dimethylbut-2-ene.
    or indeed

    dimethylbut-2-ene (redundancy)
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    (Original post by charco)
    or indeed

    dimethylbut-2-ene (redundancy)
    You could go further and just call it dimethylbutene.

    But I am straying into the world of logic problems.
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    Nah I'm wrong
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    (Original post by Naeco)
    Attachment 609724
    I thought it is this?
    Nah probably wrong
    Reading from left to right...
    C1 has three bonds and C3 has five.
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    (Original post by Pigster)
    Reading from left to right...
    C1 has three bonds and C3 has five.
    Worst chemistry time for me
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    (Original post by Naeco)
    Worst chemistry time for me
    Just so long as you learn from your mistakes and never repeat them, all you will do is improve.
 
 
 
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