An object of mass 100 kg is suspended by two identical cables. The tension in cable one is (400i + 300j)N, where i and j are horizontal and vertical unit vectors respectively. The tension in cable two is (pi + qj)N.
If the object remain at rest, find p and q
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- Thread Starter
- 08-01-2017 14:22
- 08-01-2017 16:21
Resolve vertically and horizontally as the object is at rest, so the horizontal components of the tensions would be equal and the sum of the vertical components will equal the weight of the object.