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    Please help explain? The answer is C!

    Which reagent would exactly neutralise 100 cm3 of 1.00 mol dm–3 H2SO4(aq)?

    A 0.100 mol Al(OH)3
    B 0.100 mol NH3
    C 0.100 mol Ba(OH)2
    D 0.100 mol NaOH
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    (Original post by Chem8585)
    Please help explain? The answer is C!

    Which reagent would exactly neutralise 100 cm3 of 1.00 mol dm–3 H2SO4(aq)?

    A 0.100 mol Al(OH)3
    B 0.100 mol NH3
    C 0.100 mol Ba(OH)2
    D 0.100 mol NaOH
    let's compare moles of stuff ok?

    Work out the concentration. n=\dfrac{v\times c}{1000}

    See that H_2 SO_4 has 2 H in it. So whatever you neutralise it should have 2 lots of OH in it. Or if it only has 1 lot of OH in then the Mol should be doubled.
    Pigster ^^ is this right??
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    (Original post by will'o'wisp)
    let's compare moles of stuff ok?

    Work out the concentration. n=\dfrac{v\times c}{1000}

    See that H_2 SO_4 has 2 H in it. So whatever you neutralise it should have 2 lots of OH in it. Or if it only has 1 lot of OH in then the Mol should be doubled.
    Pigster ^^ is this right??

    Thank you!... I just remembered about diprotic acids. I believe this is right, but will wait until double checked. Would you be able to answer the other chemistry question I have posted? I think I know the answer, but would like to confirm that my reasoning is correct.
    https://www.thestudentroom.co.uk/sho...624&highlight=
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    You woke me for this?

 
 
 

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