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    I need a little help with this question as I'm not sure how to draw the diagram for it so I was wondering if anyone had any idea of how to go about answering it! Thanks!

    A particle of mass 10kg is in contact with a rough horizontal surface. It is acted upon by a force of 30N acting at an angle of 40° to the surface. (In an upward direction)

    The particle accelerates along the surface constantly at 2m)s^2
    Find:
    a) the magnitude of the normal reaction
    b) the magnitude of the friction reaction
    c) the coefficient of friction
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    (Original post by Peachy23)
    I need a little help with this question as I'm not sure how to draw the diagram for it so I was wondering if anyone had any idea of how to go about answering it! Thanks!

    A particle of mass 10kg is in contact with a rough horizontal surface. It is acted upon by a force of 30N acting at an angle of 40° to the surface. (In an upward direction)

    The particle accelerates along the surface constantly at 2m)s^2
    Find:
    a) the magnitude of the normal reaction
    b) the magnitude of the friction reaction
    c) the coefficient of friction
    Here's a diagram to get you started:

    Name:  Untitled.jpg
Views: 30
Size:  11.9 KB


    a) You can resolve vertically for the normal reaction.

    b) Then, since you know the acceleration, I'd start with "Resultant force = mass x acceleration" considering the horizontal motion.

    This will give you the resultant horizontal force, from which you can work out the frictional force, etc.
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    (Original post by ghostwalker)
    Here's a diagram to get you started:

    Name:  Untitled.jpg
Views: 30
Size:  11.9 KB


    a) You can resolve vertically for the normal reaction.

    b) Then, since you know the acceleration, I'd start with "Resultant force = mass x acceleration" considering the horizontal motion.

    This will give you the resultant horizontal force, from which you can work out the frictional force, etc.
    That's how I had drawn the diagram so I'm happy to know I got it right! Thanks for the advice, I'll try to do the question
 
 
 
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