Turn on thread page Beta
    • Community Assistant
    • Study Helper
    Offline

    20
    ReputationRep:
    Community Assistant
    Study Helper
    (Original post by student004)
    do past papers forget about everything else
    Past papers are not as useful as they were last year but are still good for practicing questions. 9-1 Practice papers are more useful than past papers.
    Offline

    19
    ReputationRep:
    Hey I have this rather confusing question which needs a bit of clarification.
    Name:  Copy of 1MA1 - specimen papers set 2 - 7-9 practice paper gold.doc [Compatibility Mode] - Word 1.png
Views: 59
Size:  2.8 KB

    So I worked the equation of L to be y=\frac{20}{3}-\frac{1}{3}x which crosses the y axsis at (0,\frac{20}{3}) However, point O hasn't be defined, so assuming it means the center (0, 0) would the area of the triangle be \frac{20 \sqrt 10}{9} ?
    • Community Assistant
    • Study Helper
    Offline

    20
    ReputationRep:
    Community Assistant
    Study Helper
    (Original post by CraigBackner)
    Hey I have this rather confusing question which needs a bit of clarification.
    Name:  Copy of 1MA1 - specimen papers set 2 - 7-9 practice paper gold.doc [Compatibility Mode] - Word 1.png
Views: 59
Size:  2.8 KB

    So I worked the equation of L to be y= \frac{20}{3}- \frac{1}{3}x which crossed the x axsis at (0,\frac{20}{3}) However, point O hasn't be defined, so assuming it means the center (0, 0) would the area of the triangle be \frac{20 \sqrt 10}{9} ?
    Yes O is (0, 0) and that would be made clearer in a real exam question.

    It crosses the y-axis at (0, 20/3), not the x-axis.
    Offline

    19
    ReputationRep:
    (Original post by notnek)
    Yes O is (0, 0) and that would be made clearer in a real exam question.

    It crosses the y-axis at (0, 20/3), not the x-axis.
    Ok yeah my bad.
    So knowing this, the length of the triangle are \sqrt40, (given by the radius), \frac{20}{3} (given by the difference of the two points ,(0,\frac{20}{3}), (0, 0) and \frac{40}{9} (by Pythagoras theorem).
    Therefore the area is \frac{b*h}{2} which should give \frac{40\sqrt10}{9}. However the mark scheme answer is 60 Is this correct and if so how?

    Name:  Copy of 1MA1 - specimen papers set 2 - 7-9 practice paper gold.doc [Compatibility Mode] - Word 1.png
Views: 54
Size:  3.5 KB
    Offline

    18
    ReputationRep:
    (Original post by CraigBackner)
    Ok yeah my bad.
    So knowing this, the length of the triangle are \sqrt40, (given by the radius), \frac{20}{3} (given by the difference of the two points ,(0,\frac{20}{3}), (0, 0) and \frac{40}{9} (by Pythagoras theorem).
    Therefore the area is \frac{b*h}{2} which should give \frac{20\sqrt10}{9}. However the mark scheme answer is 60 Is this correct and if so how?

    Name:  Copy of 1MA1 - specimen papers set 2 - 7-9 practice paper gold.doc [Compatibility Mode] - Word 1.png
Views: 54
Size:  3.5 KB
    It is referencing the x-intercept of the tangent, not the circle, if you have got those confused. (the tangent intercepts the x-axis at (20,0))
    Offline

    18
    ReputationRep:
    (Original post by CraigBackner)
    Yes,yes I know that but you need to work out the area of OAP, which includes a point on the circle
    Try sketching it out if you're still unsure.
    Offline

    19
    ReputationRep:
    (Original post by _gcx)
    It is referencing the x-intercept of the tangent, not the circle, if you have got those confused. (the tangent intercepts the x-axis at (20,0))
    Ohh i see now,thanks
    Offline

    14
    ReputationRep:
    (Original post by Misaki24)
    My teacher said the grade boundary has already been set for this year and any changes would only apply to the year 10s im confused now :P
    But how can the grade boundaries already be set if the whole point of grade boundaries is to see how the whole nation did as a whole and then setting the ranges of the marks to achieve certain grades.
    Offline

    17
    ReputationRep:
    do this one:
    nice and easy

    make "q" the subject of the formula 5(q+p)=4+8p
    give your answer in it simplest form

    (Original post by NothingButWaleed)
    But how can the grade boundaries already be set if the whole point of grade boundaries is to see how the whole nation did as a whole and then setting the ranges of the marks to achieve certain grades.
    Offline

    14
    ReputationRep:
    (Original post by unillama)
    do this one:
    nice and easy

    make "q" the subject of the formula 5(q+p)=4+8p
    give your answer in it simplest form
    No Problem....

    Expand: 5q+5p = 4+8p
    Rearrange: 5q = 4+8p-5p

    Final Touches: q = (4+8p-5p)/5
    :aetsch::aetsch::aetsch::aetsch::aetsch::aetsch:
    Offline

    17
    ReputationRep:
    (Original post by NothingButWaleed)
    No Problem....

    Expand: 5q+5p = 4+8p
    Rearrange: 5q = 4+8p-5p

    Final Touches: q = (4+8p-5p)/5
    YOU WOULD ONLY GET 2 MARKS FOR THAT
    READ THE QUES AGAIN :aetsch::aetsch::aetsch::aetsch::aetsch::aetsch:
    Offline

    14
    ReputationRep:
    (Original post by unillama)
    YOU WOULD ONLY GET 2 MARKS FOR THAT
    READ THE QUES AGAIN :aetsch::aetsch::aetsch::aetsch::aetsch::aetsch:
    Oh shame "Simplest form"
    q = (4+3p)/5

    Lol, see this is the kind of stupid mistakes I make in the exam....
    Offline

    17
    ReputationRep:
    its ok this is the only place you should make the mistakes not in the exam!!
    you learn from mistakes so make them but dont repeat them!!
    xx
    (Original post by NothingButWaleed)
    Oh shame "Simplest form"
    q = (4+3p)/5

    Lol, see this is the kind of stupid mistakes I make in the exam....
    Offline

    14
    ReputationRep:
    (Original post by unillama)
    its ok this is the only place you should make the mistakes not in the exam!!
    you learn from mistakes so make them but dont repeat them!!
    xx
    True....watch me still make the same mistake in the exam *facepalm*. Lol..retard alert!
    Offline

    17
    ReputationRep:
    lol!!
    (Original post by NothingButWaleed)
    True....watch me still make the same mistake in the exam *facepalm*. Lol..retard alert!
    Offline

    19
    ReputationRep:
    Hey can someone explain the understanding to this question?

    A gardener wants to estimate the number of snails in his garden.
    One day he catches 95 snails. He puts a tag on each snails then releases them.
    Then next day the gardener catches 164 snails.
    68 of these snails have a tag on them.
    Work out an estimate for the total number of snails in his garden.
    Write down any assumptions you have made.

    Then answer is \frac{(95) × (164)}{68}=229 snails because 95 of the snails make \frac{68}{164} of the population. But whys that?
    Offline

    18
    ReputationRep:
    (Original post by CraigBackner)
    Hey can someone explain the understanding to this question?

    A gardener wants to estimate the number of snails in his garden.
    One day he catches 95 snails. He puts a tag on each snails then releases them.
    Then next day the gardener catches 164 snails.
    68 of these snails have a tag on them.
    Work out an estimate for the total number of snails in his garden.
    Write down any assumptions you have made.

    Then answer is \frac{(95) × (164)}{68}=229 snails because 95 of the snails make \frac{68}{164} of the population. But whys that?
    We assume that the sample that has been taken is representative of the population. Thus, as \frac{68}{164} of the snails collected have been tagged, we can assume that we have tagged \frac{68}{164} of the population (again, making the assumption that it is representative), and hence \frac{68}{164}x=95, from which you can find the population.
    • Community Assistant
    • Study Helper
    Offline

    20
    ReputationRep:
    Community Assistant
    Study Helper
    (Original post by CraigBackner)
    Hey can someone explain the understanding to this question?

    A gardener wants to estimate the number of snails in his garden.
    One day he catches 95 snails. He puts a tag on each snails then releases them.
    Then next day the gardener catches 164 snails.
    68 of these snails have a tag on them.
    Work out an estimate for the total number of snails in his garden.
    Write down any assumptions you have made.

    Then answer is \frac{(95) × (164)}{68}=229 snails because 95 of the snails make \frac{68}{164} of the population. But whys that?
    I've seen questions similar to this in lots of the 9-1 practice papers. I'm not sure what the obsession is
    Offline

    19
    ReputationRep:
    Hey I'm really stuck on this question because the answer I'm getting is not the same as the markscheme.
    Name:  Edexcel GCSE (9-1) Mathematics_ Higher Student Book (Edexcel GCSE Maths 2015) - Google Chrome 26.png
Views: 52
Size:  77.7 KB

    I worked out the two equal lengths of the isosceles triangle to be 13 because of Pythagorean triples, 5,12  and 13
    The using \frac{1}{2}absinx=42. I rearranged for Sin x to give  = sin^-1(\frac{84}{a^2}) then subbing in 13 for a and solving I get 29.8.. however the markscheme answer is 32.5
    Anyone know why?
    • Community Assistant
    • Study Helper
    Offline

    20
    ReputationRep:
    Community Assistant
    Study Helper
    (Original post by CraigBackner)
    Hey I'm really stuck on this question because the answer I'm getting is not the same as the markscheme.

    I worked out the two equal lengths of the isosceles triangle to be 13 because of Pythagorean triples, 5,12  and 13
    Where did you get 5 from?

    The first step is to use the fact that the area is 42 to find the length of the base. Have you done this?
 
 
 
Reply
Submit reply
Turn on thread page Beta
Updated: June 10, 2017

University open days

  • Sheffield Hallam University
    City Campus Postgraduate
    Wed, 17 Oct '18
  • Staffordshire University
    Nursing and Midwifery Undergraduate
    Wed, 17 Oct '18
  • Teesside University
    Undergraduate open day Undergraduate
    Wed, 17 Oct '18
Poll
Who is most responsible for your success at university
Useful resources

Make your revision easier

Maths

Maths Forum posting guidelines

Not sure where to post? Read the updated guidelines here

Equations

How to use LaTex

Writing equations the easy way

Equations

Best calculators for A level Maths

Tips on which model to get

Student revising

Study habits of A* students

Top tips from students who have already aced their exams

Study Planner

Create your own Study Planner

Never miss a deadline again

Polling station sign

Thinking about a maths degree?

Chat with other maths applicants

Can you help? Study help unanswered threads

Groups associated with this forum:

View associated groups

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.