Turn on thread page Beta
    • Thread Starter
    Offline

    10
    ReputationRep:
    Name:  IMG_0321.jpg
Views: 34
Size:  407.1 KB

    Question 13 folks, been at it for a while and I can't get it. To me it seems like something is missing from the question?

    Edit: the workings I've done is me trying to work backwards from the answers given
    • Thread Starter
    Offline

    10
    ReputationRep:
    (Original post by Dav1dJG)
    Name:  IMG_0321.jpg
Views: 34
Size:  407.1 KB

    Question 13 folks, been at it for a while and I can't get it. To me it seems like something is missing from the question?

    Edit: the workings I've done is me trying to work backwards from the answers given
    Smack
    • TSR Support Team
    Offline

    20
    ReputationRep:
    TSR Support Team
    (Original post by Dav1dJG)
    Smack
    I'm on it.
    • TSR Support Team
    Offline

    20
    ReputationRep:
    TSR Support Team
    Is there some sort of rule of thumb regarding sheet metal that I am missing? It seems quite hard to do this without knowing the pressing force, unless we are to attempt to solve it iteratively.
    • Thread Starter
    Offline

    10
    ReputationRep:
    (Original post by Smack)
    Is there some sort of rule of thumb regarding sheet metal that I am missing? It seems quite hard to do this without knowing the pressing force, unless we are to attempt to solve it iteratively.
    Nope. Apparently everything is there.
    I emailed my lecturer for tips last night. All he said was that the shear and compressive stresses both have to be in terms of Force and substituted into the other equations.
    Which confused me even more hahaha.
    • TSR Support Team
    Offline

    20
    ReputationRep:
    TSR Support Team
    (Original post by Dav1dJG)
    Nope. Apparently everything is there.
    I emailed my lecturer for tips last night. All he said was that the shear and compressive stresses both have to be in terms of Force and substituted into the other equations.
    Which confused me even more hahaha.
    Does it have to be solved by hand, i.e. manipulating the equations and performing algebra?
    • Thread Starter
    Offline

    10
    ReputationRep:
    (Original post by Smack)
    Does it have to be solved by hand, i.e. manipulating the equations and performing algebra?
    I think that's what is required. As I said though, I've tried working backwards from the answer n still got nowhere.
    64mm diameter and 128.7kN respectively
    • TSR Support Team
    Offline

    20
    ReputationRep:
    TSR Support Team
    (Original post by Dav1dJG)
    I think that's what is required. As I said though, I've tried working backwards from the answer n still got nowhere.
    64mm diameter and 128.7kN respectively
    I just solved it iteratively using Excel and arrived at those answers. Can't help with the algebra though I'm afraid.
    • Thread Starter
    Offline

    10
    ReputationRep:
    (Original post by Smack)
    I just solved it iteratively using Excel and arrived at those answers. Can't help with the algebra though I'm afraid.

    That's cool man cheers for trying. I've got dynamics first thing tomorrow, that lecturer teaches statics aswell though so I'll get his help to solve it, take a photo n post back! I've got this statics exam tomorrow. Hopefully nothing this bad! Frameworks and beam bending moment diagrams are a cakewalk compared to that lol
    Offline

    11
    ReputationRep:
    What exam board is it??
    Offline

    18
    ReputationRep:
    (Original post by Dav1dJG)
    ...
    I just ran through my (non-iterative) calculations and managed to arrive at 64mm and 128.7kN for the solution.

    The essential steps for the maximum diameter are:

    1) Work out the shear force at yield by making use of the shear yield stress and the relevant reference area.

    2) Equilibrate the shear force with the compressive yield stress of the punch.

    For the minimum force, you should again equilibrate the shear force at the point of yielding due to shear, making sure to use the correct relevant reference area.

    The steps use only very basic algebra, so it should be quite easy if you follow the above steps.

    Good luck!

    Edit: Forgot to mention that you should definitely make a plane stress assumption for the steel sheet. That should make life a lot easier!
 
 
 
Reply
Submit reply
Turn on thread page Beta
Updated: January 12, 2017

University open days

  • University of Warwick
    Undergraduate Open Days Undergraduate
    Sat, 20 Oct '18
  • University of Sheffield
    Undergraduate Open Days Undergraduate
    Sat, 20 Oct '18
  • Edge Hill University
    Faculty of Health and Social Care Undergraduate
    Sat, 20 Oct '18
Poll
Who is most responsible for your success at university

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.