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    (Original post by theeconomistkid)
    I got 2*10^10 and volume of the liquid.. because no matter how much volume you have it doesn't affect how sticky your caramel is gonna be right?
    Haha true that but for the gradient did u get 714.28 the gradient not young modulous
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    Exam was overall good. I am expecting there to be a high grade boundary.
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    (Original post by Hola1234)
    Haha true that but for the gradient did u get 714.28 the gradient not young modulous
    YES GURL I GOT IT!!!!!! I JUST RE USED THE VALUES FROM THE TABLE LOL AND USED (0,0) as well
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    (Original post by theeconomistkid)
    YES GURL I GOT IT!!!!!! I JUST RE USED THE VALUES FROM THE TABLE LOL AND USED (0,0) as well
    Ok but what was ur actual value for gradient
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    what values for force and extension did u guys use to get 2*10^10?
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    what was ans for percentage uncertainty?


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    (Original post by ree.x09)
    what was ans for percentage uncertainty?


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    I got 6%
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    (Original post by Ultnari)
    I got 6%
    Percentage uncertainty was 1.7%
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    (Original post by AdemN)
    Percentage uncertainty was 1.7%
    Yeh even I got that
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    How did you calculate the percentage uncertainty
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    (Original post by AdemN)
    Percentage uncertainty was 1.7%
    For the percentage uncertainty weren't we supposed to change 0.01mm into cm then divide it by 6 and multiply it by 100?
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    (Original post by zenab_k)
    For the 6cm was it like the burns occur at nodes therefore one wavelength is distance btw 2 nodes
    It's two antinodes!
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    (Original post by zenab_k)
    For the percentage uncertainty weren't we supposed to change 0.01mm into cm then divide it by 6 and multiply it by 100?
    The uncertainty was +/- 1mm
    Therefore the percenage uncertainty is 1/60 *100 which gives 1.7%
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    (Original post by mandax_25)
    The uncertainty was +/- 1mm
    Therefore the percenage uncertainty is 1/60 *100 which gives 1.7%
    Uncertainty on metre rule is +/- 0.5mm, 0.5/60 = 0.83%
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    Guys I got 1.99X10^8 for young modulus I found it by using the formula (force x original length) / (cross sectional area x change in length )
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    (Original post by Luj99)
    Guys I got 1.99X10^8 for young modulus I found it by using the formula (force x original length) / (cross sectional area x change in length )
    Did you remember to convert everything to metres?
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    Would I get mark for including unit (Nm^-2) in last question but no answer
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    (Original post by theeconomistkid)
    Did you remember to convert everything to metres?
    I think I did and how did your force against extension graph look like ?
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    (Original post by Chapers64)
    Would I get mark for including unit (Nm^-2) in last question but no answer
    I think they give marks for the units and formula
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    was it supposed to be 1.91 x 10^10 ???
    (Original post by Luj99)
    Guys I got 1.99X10^8 for young modulus I found it by using the formula (force x original length) / (cross sectional area x change in length )
 
 
 

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