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# Edexcel IAL Physics Unit 03 WPH03 - 10th of May, 2017 watch

1. (Original post by shahida sulaiman)
how did u calculate it ?
I used the extrapolation method (which I think most people did). You didn't need to find the gradient. I used a random force value that was in the linear section of the graph and extrapolated to find the corresponding extension value. Then i just used the formula and got the answer.....most people seem to have got around 2x10^10!

i was just wondering if there would be a range cuz I got 2.01x10^10!

Thanks
2. (Original post by examhater44)
I used the extrapolation method (which I think most people did). You didn't need to find the gradient. I used a random force value that was in the linear section of the graph and extrapolated to find the corresponding extension value. Then i just used the formula and got the answer.....most people seem to have got around 2x10^10!

i was just wondering if there would be a range cuz I got 2.01x10^10!

Thanks
I did the same and got the the answer as 1.98x10^10
3. (Original post by ahamed2000)
its not practical to measure distance in food using vernier caliper , i guess you will have to cut it to keep it in the vernier , so its not very practical to use vernier even though its more precise
do u rmmbr what u did for the very first question about the drawing of the waves?
i just drew one wave n not its reflected wave!! will i get marks?
4. (Original post by ashmjj)
do u rmmbr what u did for the very first question about the drawing of the waves?
i just drew one wave n not its reflected wave!! will i get marks?
I don't think so. I drew a standing wave with nodes and antinodes labelled and a line from 2 antinodes showing the distance between them is half lambda. Since it is at antinodes that constructive interference occurs.
5. (Original post by FutureStripper)
I don't think so. I drew a standing wave with nodes and antinodes labelled and a line from 2 antinodes showing the distance between them is half lambda. Since it is at antinodes that constructive interference occurs.
damn x/ but i drew the antinodes and clearly showed the burn marks on antinodes and indicated the distance between 2 antinodes is half lambda...just dint draw the reflected wave
6. (Original post by ashmjj)
damn x/ but i drew the antinodes and clearly showed the burn marks on antinodes and indicated the distance between 2 antinodes is half lambda...just dint draw the reflected wave
We don't need to draw the reflected wave yeah
7. (Original post by Ackashh05012911)
We don't need to draw the reflected wave yeah
most ppl are saying we need to! n why not cux that's how a standing wave is formed isnt it?
8. (Original post by ashmjj)
most ppl are saying we need to! n why not cux that's how a standing wave is formed isnt it?
It's because they clearly stated in the question that standing wave is formed.dw tho seriously I'm sure you'll get a few marks if you wrote that. I think aslong as you labelled antinodes on a wave and showed D between them is half lambda you have 2 marks guaranteed.
9. (Original post by ashmjj)
most ppl are saying we need to! n why not cux that's how a standing wave is formed isnt it?
I drew both waves and labelled 2 antinodes and showed that the distance between them is half lamda and explained that the burn marks occur at antinodes so multiplying the length between the burn marks gives the wavelength
Will I get full marks?
10. (Original post by FutureStripper)
It's because they clearly stated in the question that standing wave is formed.dw tho seriously I'm sure you'll get a few marks if you wrote that. I think aslong as you labelled antinodes on a wave and showed D between them is half lambda you have 2 marks guaranteed.
I thought the whole question was for 2 marks
11. (Original post by Ackashh05012911)
I thought the whole question was for 2 marks
I also remember the whole question being 2 marks, Im thinking 1 mark for explanation and 1 for diagram.
12. (Original post by FutureStripper)
I don't think so. I drew a standing wave with nodes and antinodes labelled and a line from 2 antinodes showing the distance between them is half lambda. Since it is at antinodes that constructive interference occurs.
Same here.
13. (Original post by wyzzl)
Hey guys! any predictions for the grade boundaries?
Is 35 or 36 out of 40 gonna be A?
Thats way to high. A paper at similiar difficulty had a boundary of 30/40 A. This exam had the first and last question to trick a few points out of people. Im thinking Max 32/40 A
14. (Original post by christos123456)
I got the same!
Same
I also remember the whole question being 2 marks, Im thinking 1 mark for explanation and 1 for diagram.
Yeah that's what I was thinking
16. (Original post by ashmjj)
damn x/ but i drew the antinodes and clearly showed the burn marks on antinodes and indicated the distance between 2 antinodes is half lambda...just dint draw the reflected wave
If the question is for 2 marks then you'll lose only 1 mark so dw
17. (Original post by Ackashh05012911)
I thought the whole question was for 2 marks
Damn okay then you shouldnt be worrying too much if your answer was along those lines
18. (Original post by Chapers64)
Passed limit of proportionality at 5.9N and then started curving I think
Mine was same !!! Thank god
19. (Original post by examhater44)
I used the extrapolation method (which I think most people did). You didn't need to find the gradient. I used a random force value that was in the linear section of the graph and extrapolated to find the corresponding extension value. Then i just used the formula and got the answer.....most people seem to have got around 2x10^10!

i was just wondering if there would be a range cuz I got 2.01x10^10!

Thanks
I did the same thing but i got 1.5x10^10 XD !! Hope its right ? Which values you used ?
20. (Original post by Muaaz Iqbal)
I did the same thing but i got 1.5x10^10 XD !! Hope its right ? Which values you used ?
For questions like these, they usually give a huge range or they'll give mark if the power is correct. So let's hope your answer is in their range

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