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Equilibrium Watch

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    Hi guys,
    I have one question, I think you may find it a bit silly but can anyone explain it to me pleaseee.
    So:
    The reversible reaction A + B --> C + D reaches the equilibrium.
    At the beginning 2 moles of A and 1 mole of B are mixed.
    Now my question is:
    If the ratio in the equation is 1:1, how come the amounts of A and B can be different ?

    Thanks
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    If you consider another (non-equilibrium) reaction:

    HCl + NaOH -> NaCl + H2O

    ...if you started with 2 mol of HCl and 1 mol of NaOH, what would you be left with?
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    (Original post by Pigster)
    If you consider another (non-equilibrium) reaction:

    HCl + NaOH -> NaCl + H2O

    ...if you started with 2 mol of HCl and 1 mol of NaOH, what would you be left with?
    Not sure
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    1 mol of HCl would react with 1 mol of NaOH. There is 1 mol of HCl remaining, but no alkali to react with it. (1 mol of NaCl and 1 mol of H2O are made).

    In your case, you started with 2 mol of A and 1 mol of B. x mol of A would react with x mol of B, leaving you with 2-x mol of A and 1-x mol of B (making x mol of C and x mol of D). What's the problem?
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    (Original post by Pigster)
    1 mol of HCl would react with 1 mol of NaOH. There is 1 mol of HCl remaining, but no alkali to react with it. (1 mol of NaCl and 1 mol of H2O are made).

    In your case, you started with 2 mol of A and 1 mol of B. x mol of A would react with x mol of B, leaving you with 2-x mol of A and 1-x mol of B (making x mol of C and x mol of D). What's the problem?
    ok now I see, its about REACTING amounts. Makes sense.
    Thank you a lot
 
 
 
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