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    MnO4- +V2+ +H+ -- VO2+ + H2O +Mn2+
    Balance using oxidation numbers?
    Thanks
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    Just quoting in Danny Dorito so she can move the thread if needed :wizard:
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    (Original post by helpme:))
    MnO4- +V2+ +H+ -- VO2+ + H2O +Mn2+
    Balance using oxidation numbers?
    Thanks
    It's pretty simple once you know the rules.

    First you balance all the elements other than H or O.... so in your case, you need to make sure that there are the same number of Mn on each side and same number of V on each side. Mn is already equal so you need to put a 2 in front of VO2 to have two V atoms on each side.

    Then you balance the Oxygen (O) by adding the necessary number of H20 on whichever side to balance it.

    Then you balance H with H+ ions

    Then you balance to overall charge on each side, so you need to insert e- electrons to either side needs it.

    Try it out and post back with your working out
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    (Original post by James A)
    It's pretty simple once you know the rules.

    First you balance all the elements other than H or O.... so in your case, you need to make sure that there are the same number of Mn on each side and same number of V on each side. Mn is already equal so you need to put a 2 in front of VO2 to have two V atoms on each side.

    Then you balance the Oxygen (O) by adding the necessary number of H20 on whichever side to balance it.

    Then you balance H with H+ ions

    Then you balance to overall charge on each side, so you need to insert e- electrons to either side needs it.

    Try it out and post back with your working out
    Hi, i understood it just today but thanks anyway.
 
 
 
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