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    (Original post by SiddzWHk)
    Guys for the observations I said that the Grey Metal Magnecium dissapears. Do you know if I'll get a mark for that?
    In all previous marking schemes it says that magnesium burns with a bright white flame. Also produces a white powder of magnesium oxide.
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    (Original post by weirdperson7878)
    what did people get for the compounds that went through the filter paper? I got water and magnesium sulfate but other people are saying that sulfuric acid went through the filter paper.
    I got the same
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    Yeah but it's an observation and theoretically it's right:/.
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    Could anyone who remembers the marks please put them on the unofficial mark scheme
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    what about the question on Carbon reacting with 0xygen? i wrote that it reacts to form Carbon dioxide which then reacts with C to to guve the reducing agent carbon monoxide
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    also what about the last question? i wrote that calcium carbide particles have more kinectic energy so frequency of successful collisions increases and the rate of reaction increases. I also mentioned about activation energy
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    Any predictions for paper 2???
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    How did it go?
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    Thought it was fine

    Electrolysis calculation was 1.27g
    The 3 gases were hydrogen, chlorine and oxygen
    The kj/mol was 403.2
    The last question was -535
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    Oh my days that was a maths exam 😳
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    What did you get for the faradays question? I got 0.02g
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    (Original post by Gneale12345)
    Thought it was fine

    Electrolysis calculation was 1.27g
    The 3 gases were hydrogen, chlorine and oxygen
    The kj/mol was 403.2
    The last question was -535
    Mate i got 405 what did you do?
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    (Original post by Starbox359)
    What did you get for the faradays question? I got 0.02g

    I got 127 g because you multiply the 0.02 by 63.5 I think
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    (Original post by solark)
    Mate i got 405 what did you do?

    I also got 403.2

    You did 18.9/(3/64)
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    (Original post by solark)
    Mate i got 405 what did you do?
    I got 18900 for the calculation above it then i found the mass of ethanol by taking away the mass after combustion from before which was 1.5g
    The moles was 1.5g/32 which gave me 3/64 moles.

    3/64 moles = 18900J
    18900/ 3/64 gave you one mole which was 403200J
    /1000 gave u 403.2
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    (Original post by Gneale12345)
    I got 18900 for the calculation above it then i found the mass of ethanol by taking away the mass after combustion from before which was 1.5g
    The moles was 1.5g/32 which gave me 3/64 moles.

    3/64 moles = 18900J
    18900/ 3/64 gave you one mole which was 403200J
    /1000 gave u 403.2
    Are u able to start an unofficial mark scheme
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    (Original post by Gneale12345)
    I got 18900 for the calculation above it then i found the mass of ethanol by taking away the mass after combustion from before which was 1.5g
    The moles was 1.5g/32 which gave me 3/64 moles.

    3/64 moles = 18900J
    18900/ 3/64 gave you one mole which was 403200J
    /1000 gave u 403.2
    Yeah i rounded up 18900 to 19kj thats why thanks
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    (Original post by solark)
    How did it go?
    Was quite hard in some parts. Too much organic chemistry.
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    (Original post by Starbox359)
    I also got 403.2

    You did 18.9/(3/64)
    I think 403.2 was wrong. The reaction was exothermic, and therefore you had to use a minus for the temperature change.
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    (Original post by Gneale12345)
    Thought it was fine

    Electrolysis calculation was 1.27g
    The 3 gases were hydrogen, chlorine and oxygen
    The kj/mol was 403.2
    The last question was -535
    I did not get the electrolysis calculation.
    I got 3 gases as hydrogen (for negative electrode), water and chlorine gas for positive electrode.

    3 half equations:
    2Cl- + 2e- -> Cl2
    2H+ + 2e- -> H2
    H+ + OH- -> H2O

    I got something negative for the kj/mol, because you had to use negative temperature change (exothermic reaction)

    Can't remember what I got for the last question.
 
 
 
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