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Edexcel IAL Mathematics C34- 17th January, 2017 Watch

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    (Original post by palpol)
    Does anyone remember how much marks that time question you were discussing had?
    The whole thing? 11 marks I reckon.
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    My paper went okay but 14 questions+parallelogram + cartesean equation were a surprise
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    (Original post by Stoke123)
    I'm going to do the Exam in June.

    Any tips for me?
    Practice loads. That's all there is to it really.
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    (Original post by Hamzah249)
    Yeah I guess you are right, I couldn't figure out this question till the very end because part b specifically stated a "Second model" has equation etc etc so I tried to work on it with only what was given in part b.
    Tried to rush through the question and I guess I got wrong lambda :/
    Are you referring to the ice question? Couldn't finish that due to lack of time :cry:
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    (Original post by sabahshahed294)
    My paper went okay but 14 questions+parallelogram + cartesean equation were a surprise
    Solution to cartesian was sec^2 = tan^2 + 1 identity, what did you do?
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    (Original post by sabahshahed294)
    Are you referring to the ice question? Couldn't finish that due to lack of time :cry:
    yeah
    I got my integration in it so thats 3 marks, substituted t=3 and x=1.5 so thats another mark.
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    (Original post by Hamzah249)
    Solution to cartesian was sec^2 = tan^2 + 1 identity, what did you do?
    I didn't realise that we have to substitute it into the cartesean equation hence I left it.

    (Original post by Hamzah249)
    yeah
    I got my integration in it so thats 3 marks, substituted t=3 and x=1.5 so thats another mark.
    Oh damn. Bad luck for me. I was planning to do the integration sum but then I lacked time. I thought the paper had 12 questions hence I went a bit slow. Later I see 14 and then I rushed :/
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    Does anyone know the answers to these questions?

    - After you prove tan 3A = something. It asks to work out -30 < x < 30 for tan 3x = 11 tan x

    - ∫ 120 (x / (2x + 3)2) dx by substituting u = 2x + 3 to form 1/2 ln 3 = 2/9
    What type of integration where you suppose to use?

    - The question with the trapezium rule, what were the exact values of y?

    - The question with y = x cos x
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    (Original post by Stoke123)
    I'm going to do the Exam in June.

    Any tips for me?
    Practice And use the videos for exam solutions. Especially for topics such as differentiation and integration as he explains them very well.
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    (Original post by Raynedrops)
    Does anyone know the answers to these questions?

    - After you prove tan 3A = something. It asks to work out -30 < x < 30 for tan 3x = 11 tan x

    - ∫ 120 (x / (2x + 3)2) dx by substituting u = 2x + 3 to form 1/2 ln 3 = 2/9
    What type of integration where you suppose to use?

    - The question with the trapezium rule, what were the exact values of y?

    - The question with y = x cos x
    For the first one, you worked out tan 3x in the previous part so simply substitute what you worked out for tan 3x and then a cubic equation forms.
    Second one: Integration by Substitution
    Third one: I don't remember what were the values given but the values were coming in the form of pi.
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    (Original post by Raynedrops)
    Does anyone know the answers to these questions?

    - After you prove tan 3A = something. It asks to work out -30 < x < 30 for tan 3x = 11 tan x

    - ∫ 120 (x / (2x + 3)2) dx by substituting u = 2x + 3 to form 1/2 ln 3 = 2/9
    What type of integration where you suppose to use?

    - The question with the trapezium rule, what were the exact values of y?

    - The question with y = x cos x
    -Trapezium rule 2nd value of y was 9piunderroot5/8 I dont remember the first value. (Not sure about this)

    -12 to 0 integration. It was basic integration stuff once you substitute u you end up with u-3/u^2.

    - tan3x=11tanx you can still figure it out, use tan3x = tan(2x+x)
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    (Original post by Raynedrops)
    Does anyone know the answers to these questions?

    - After you prove tan 3A = something. It asks to work out -30 < x < 30 for tan 3x = 11 tan x
    If memory serves right, I think it was x=0, 26.95, -26.95
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    (Original post by Hamzah249)
    If memory serves right, I think it was x=0, 26.95, -26.95
    YAS
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    Guys how much do you think will be the raw mark out of 125 for an A*?
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    (Original post by wenogk)
    Guys how much do you think will be the raw mark out of 125 for an A*?
    Considering it was easy, 108 or above for a* BUT lots of people are complaining about how lengthy paper was so that might factor in. Though I hope I'm wrong and a* is way below that like 102.
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    (Original post by Hamzah249)
    Considering it was easy, 108 or above for a* BUT lots of people are complaining about how lengthy paper was so that might factor in. Though I hope I'm wrong and a* is way below that like 102.
    Yeah my prediction would be 108-112 for A*
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    Hmmm maybe 115 to 120 I guess
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    (Original post by Cai Jianlin)
    Hmmm maybe 115 to 120 I guess
    Yeah that could actually happen because Jan 2016 was 115 for A*..
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    (Original post by wenogk)
    Yeah that could actually happen because Jan 2016 was 115 for A*..
    (Original post by Cai Jianlin)
    Hmmm maybe 115 to 120 I guess
    (Original post by sabahshahed294)
    For the first one, .
    (Original post by Raynedrops)
    Does anyone
    (Original post by Fasih178)
    Practice loads.
    Please tag me in model answers when ever it's released.
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    (Original post by Hamzah249)
    Please tag me in model answers when ever it's released.
    Sure.
 
 
 
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