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    Trying to help a friend with some maths for his apprenticeship but don't remember much from hyperbolic equations at college. I remember that cosh(x) can become (e^x + e^-x)/2 but I'm not sure how to simplify to that from cosh(ax) where a = 1/2. Had ideas about cosh(x/2) becoming cosh^(1/2) (x) + sinh^(1/2) (x) using equation 17 rule here http://www.alcyone.com/max/reference...yperbolic.html but I'm really out of my depth with this. Any help would be hugely appreciated. Only need help for question 2, should be able to work out question 3 after that

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    (Original post by Acsel)
    You may recall that \cosh 0 = 1 so 4 \cosh 0 = 4 and (0, 4) is the minimum point. You just need to substitute x = 1.5 into the equation for h. There is no need to consider exponential form.
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Updated: January 13, 2017
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