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    How do you solve this :log(base3)x-4log(base x)3=0

    I have managed to do equations like this before but I cannot do this one for some reason

    Please help
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    (Original post by Mf1999)
    How do you solve this :log(base3)x-4log(base x)3=0

    I have managed to do equations like this before but I cannot do this one for some reason

    Please help
    First of all you need to make sure that both logs have the same base, using this formula

    Then once they both have the same base, you apply normal log laws to get it as one singular logarithm
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    (Original post by KaylaB)
    First of all you need to make sure that both logs have the same base, using this formula

    Then once they both have the same base, you apply normal log laws to get it as one singular logarithm
    Thank u so much
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    (Original post by Mf1999)
    Thank u so much
    No problem! :hat2:
 
 
 
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