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    Hi did maths exam and I was hoping someone could tell me what year it was from as it had no cover I remember the last question being about working out circumference of a sector and the angle was 30 degrees and a shaded area was 100cm
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    Hi I did the same paper today , and completely forgot to do the last page ( luckily it was only a mock) , was that the final question of the paper , and if you did the same paper what di you get for the simplify question . ( 50x squared-8 divided by 10x-4 , thannks in advance
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    (Original post by Halloumi)
    Hi I did the same paper today , and completely forgot to do the last page ( luckily it was only a mock) , was that the final question of the paper , and if you did the same paper what di you get for the simplify question . ( 50x squared-8 divided by 10x-4 , thannks in advance
     \displaystyle \frac{50x^2-8}{10x-4}=\frac{2(25x^2-4)}{2(5x-2)}=\frac{(5x-2)(5x+2)}{5x-2}=5x+2 however this is not strictly true as if you let x=0.4 in the expression  \frac{50x^2-8}{10x-4} you have a problem as you're dividing by 0, but if you put x=0.4 into the simplified expression you get 4 and so you can see that the simplification has introduce a problem somewhat. You would not be expected to think about any of this at this level but I think it's good for you to think about.
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    Phew got it right but still annoyed by the fact i missed the last page thanks very much
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    bro do you know what paper it was


    (Original post by B_9710)
     \displaystyle \frac{50x^2-8}{10x-4}=\frac{2(25x^2-4)}{2(5x-2)}=\frac{(5x-2)(5x+2)}{5x-2}=5x+2 however this is not strictly true as if you let x=0.4 in the expression  \frac{50x^2-8}{10x-4} you have a problem as you're dividing by 0, but if you put x=0.4 into the simplified expression you get 4 and so you can see that the simplification has introduce a problem somewhat. You would not be expected to think about any of this at this level but I think it's good for you to think about.
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    (Original post by Lividpencil99)
    bro do you know what paper it was
    No.
 
 
 
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