Turn on thread page Beta
    • Thread Starter
    Offline

    5
    ReputationRep:
    Hello, I am stuck Exercise 3I, question 6 in the Edexcel M1 textbook and even though I have the answer on the solution bank I still do not understand how they got to the answer. Could someone please explain it to me?

    I hope that everyone is having a good weekend

    Name:  help.png
Views: 142
Size:  46.0 KB
    • Community Assistant
    Offline

    17
    ReputationRep:
    Community Assistant
    Hello I have moved this to maths for you.

    Which part of the solution do you not understand?
    • Thread Starter
    Offline

    5
    ReputationRep:
    (Original post by rayquaza17)
    Hello I have moved this to maths for you.

    Which part of the solution do you not understand?
    Thanks for moving the thread! I'm having trouble with pretty much all of part A - the only thing I understand is why the sum of the forces is equal to 0.
    • Community Assistant
    • Very Important Poster
    Offline

    20
    ReputationRep:
    Community Assistant
    Very Important Poster
    (Original post by Bunnell)
    Thanks for moving the thread! I'm having trouble with pretty much all of part A - the only thing I understand is why the sum of the forces is equal to 0.
    Friction is opposing the movement of the particle up the plane so we know that it's acting down the plane. We can resolve this to be F \sin \alpha acting downwards. Note that coefficient of friction is 0.5 and we also know that F= \mu R so F \sin \theta = 0.5R\sin \alpha. When you resolve vertically, the only other forces to consider are the reaction force and the weight of the particle.

    You now have the algebraic equation with unknown R that's shown in the MS and can go on to solve it.
    • Thread Starter
    Offline

    5
    ReputationRep:
    (Original post by Kvothe the Arcane)
    Friction is opposing the movement of the particle up the plane so we know that it's acting down the plane. We can resolve this to be F \sin \alpha acting downwards. Note that coefficient of friction is 0.5 and we also know that F= \mu R so F \sin \theta = 0.5R\sin \alpha. When you resolve vertically, the only other forces to consider are the reaction force and the weight of the particle.

    You now have the algebraic equation with unknown R that's shown in the MS and can go on to solve it.
    oh my gosh thanks i finally got it! you're a star
 
 
 
Reply
Submit reply
Turn on thread page Beta
Updated: January 16, 2017
Poll
Do you think parents should charge rent?
Useful resources

Make your revision easier

Maths

Maths Forum posting guidelines

Not sure where to post? Read the updated guidelines here

Equations

How to use LaTex

Writing equations the easy way

Student revising

Study habits of A* students

Top tips from students who have already aced their exams

Study Planner

Create your own Study Planner

Never miss a deadline again

Polling station sign

Thinking about a maths degree?

Chat with other maths applicants

Can you help? Study help unanswered threads

Groups associated with this forum:

View associated groups

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.