Hey there! Sign in to join this conversationNew here? Join for free
    • Thread Starter
    Offline

    4
    ReputationRep:
    Hello, I am stuck Exercise 3I, question 6 in the Edexcel M1 textbook and even though I have the answer on the solution bank I still do not understand how they got to the answer. Could someone please explain it to me?

    I hope that everyone is having a good weekend

    Name:  help.png
Views: 72
Size:  46.0 KB
    • Community Assistant
    Offline

    17
    ReputationRep:
    Hello I have moved this to maths for you.

    Which part of the solution do you not understand?
    • Thread Starter
    Offline

    4
    ReputationRep:
    (Original post by rayquaza17)
    Hello I have moved this to maths for you.

    Which part of the solution do you not understand?
    Thanks for moving the thread! I'm having trouble with pretty much all of part A - the only thing I understand is why the sum of the forces is equal to 0.
    • TSR Support Team
    • Very Important Poster
    • Reporter Team
    • Welcome Squad
    Offline

    19
    ReputationRep:
    (Original post by Bunnell)
    Thanks for moving the thread! I'm having trouble with pretty much all of part A - the only thing I understand is why the sum of the forces is equal to 0.
    Friction is opposing the movement of the particle up the plane so we know that it's acting down the plane. We can resolve this to be F \sin \alpha acting downwards. Note that coefficient of friction is 0.5 and we also know that F= \mu R so F \sin \theta = 0.5R\sin \alpha. When you resolve vertically, the only other forces to consider are the reaction force and the weight of the particle.

    You now have the algebraic equation with unknown R that's shown in the MS and can go on to solve it.
    • Thread Starter
    Offline

    4
    ReputationRep:
    (Original post by Kvothe the Arcane)
    Friction is opposing the movement of the particle up the plane so we know that it's acting down the plane. We can resolve this to be F \sin \alpha acting downwards. Note that coefficient of friction is 0.5 and we also know that F= \mu R so F \sin \theta = 0.5R\sin \alpha. When you resolve vertically, the only other forces to consider are the reaction force and the weight of the particle.

    You now have the algebraic equation with unknown R that's shown in the MS and can go on to solve it.
    oh my gosh thanks i finally got it! you're a star
 
 
 
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • Poll
    Did TEF Bronze Award affect your UCAS choices?
    Useful resources

    Make your revision easier

    Maths

    Maths Forum posting guidelines

    Not sure where to post? Read the updated guidelines here

    Equations

    How to use LaTex

    Writing equations the easy way

    Student revising

    Study habits of A* students

    Top tips from students who have already aced their exams

    Study Planner

    Create your own Study Planner

    Never miss a deadline again

    Polling station sign

    Thinking about a maths degree?

    Chat with other maths applicants

    Can you help? Study help unanswered threads

    Groups associated with this forum:

    View associated groups
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

    Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

    Quick reply
    Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.