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Please help me with this rather large C1 Geometry Question. I'm going crazy. watch

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    For part A) I subbed in x=-3 and x=1 into the equation to find the y values, giving me y=-18 and y=18

    However, I don't know how on earth I would go on from there for part A to answer the question. Please could you help me and explain what to do and why?

    For part B, I guess it would because they have the same gradient, but please could you help me with what to do for that one?

    And just explain how to do c, d, e if you could please, but im mainly focusing on parts A and B atm.

    Thanks a lot, I appreciate it. This question has got me so stressed.
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    (Original post by blobbybill)
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    Part A - you have 2 points. Construct a line equation going through both of them by taking the gradient between the two points use one of the points for y-y_1=m(x-x_1)

    Part B - differentiate the function and show that y'(-3)=y'(1)

    Part C - just calculate the distance PR using Pythagoras' Theorem.

    Part D - same approach as in C.

    Part E - well you can explain the reason using the information given right before part C then find the area by doing \frac{1}{2}(PQ)(QR)
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    a) use (y-y1/x-x1) to find gradient
    P(-3,-18) Q(1,18)
    so gradient=(-18-18/-3-1)=9
    using y-y1=m(x-x1)
    y-18=9(x-1)
    y=9x+9
 
 
 
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