Turn on thread page Beta
    • Thread Starter
    Offline

    10
    ReputationRep:
    Name:  image.jpg
Views: 51
Size:  495.5 KB
    The answer is 1.79*10-4
    But I do not understand how the mark scheme got to it :/ ?
    I know the ratio is 1:5
    Offline

    12
    ReputationRep:
    1) Unit conversion
    2) Mole equation
    3) Answer

    Show the whole question please.
    • Thread Starter
    Offline

    10
    ReputationRep:
    (Original post by AlphaArgonian)
    1) Unit conversion
    2) Mole equation
    3) Answer

    Show the whole question please.
    Name:  image.jpg
Views: 26
Size:  335.1 KB
    Online

    19
    ReputationRep:
    (Original post by Hazel99)
    Name:  image.jpg
Views: 26
Size:  335.1 KB
    Convert mg to grams. So 10mg to grams is 10/1000 = 0.01 grams of Fe2+

    Then, to find moles, do mass/molecular mass which is 0.01/55.8 = your answer.
    Offline

    10
    ReputationRep:
    moles = mass/mr

    10mg = 0.01g (mass)
    Fe (Iron) Mr = 55.8

    moles = 0.01/55.8

    Just remember the equation moles = mass/Mr.

    /ninjad!
    Offline

    12
    ReputationRep:
    (Original post by Hazel99)
    Name:  image.jpg
Views: 26
Size:  335.1 KB
    So yeah convert mg to g (10mg = 0.01g) then use the n=M/Mr equation
 
 
 
Reply
Submit reply
Turn on thread page Beta
Updated: January 15, 2017

University open days

  • University of Bradford
    All faculties Undergraduate
    Wed, 21 Nov '18
  • Buckinghamshire New University
    All Faculties Postgraduate
    Wed, 21 Nov '18
  • Heriot-Watt University
    All Schools Postgraduate
    Wed, 21 Nov '18
Poll
Black Friday: Yay or Nay?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.