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    in a titration 20 cm3 of 1.0 mol dm-3 nitric acid , reacted with 25 cm3 of NaOH. what is the concentration of the sodium hydroxide?
    Help me im so stuck
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    (Original post by Aqa suck my ass)
    in a titration 20 cm3 of 1.0 mol dm-3 nitric acid , reacted with 25 cm3 of NaOH. what is the concentration of the sodium hydroxide?
    Help me im so stuck
    Start by writing out the balanced equation between the reaction of these 2 chemicals.
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    (Original post by legosass)
    Start by writing out the balanced equation between the reaction of these 2 chemicals.
    I dont know what it forms tho ik that nitric acid + sodium hydroxide = ? + ?
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    (Original post by Aqa suck my ass)
    I dont know what it forms tho ik that nitric acid + sodium hydroxide = ? + ?
    You need to do a symbol equation, not a word equation.

    So HNO3 + NaOH -> NaNO3 + H2O

    Now you know that the molar ratios are 1:1 between nitric acid and sodium hydroxide.
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    Then, work out the mols of HNO3 using the equation n=concentration*volume /1000
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    And you know the ratio is 1:1, so the mols of NaOH is the same. Then, use the equation n=c*v/1000 again, this time using the mols of NaOH and volume of NaOH used, and rearrange to get the concentration of NaOH.
 
 
 

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