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I am stuck on a Maths Mechanics M1 kinematics questions. Watch

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    (Original post by notnek)
    A slightly different method to what's already been suggested:

    If you say 't' is the time from when the second particle passes through O then at t = 0, the first particle will have been travelling for 5 seconds i.e. t + 5. So you get

    Second particle:

    u= 3
    a = 5.4
    t = t

    First particle:

    u = 0
    a = 3.2
    t = t + 5

    Then you can equate the two displacements.

    EDIT : Well it hadn't been suggested before I started writing this post
    Again I have tried this, but got an unsolvable eqn.
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    (Original post by Raeve)
    Again I have tried this, but got an unsolvable eqn.
    Please post your working. The equation is solvable.
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    (Original post by notnek)
    EDIT : Well it hadn't been suggested before I started writing this post
    :ninja:
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    (Original post by notnek)
    Please post your working. The equation is solvable.
    I had 1.6(t+5)^2
    (1.6t^2 + 16t + 40)
    and 3t+2.7t^2

    I equated them and put everything on one side to get:

    1.1t^2-13t-40=0

    am I doing this wrong?
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    (Original post by Raeve)
    I had 1.6(t+5)^2
    (1.6t^2 + 16t + 40)
    and 3t+2.7t^2

    I equated them and put everything on one side to get:

    1.1t^2-13t-40=0

    am I doing this wrong?
    That's correct. You can use the quadratic formula to solve it.
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    Oh wow. I have been doing it right for the last 2 hours but using an online calculator online which didn't solve it correctly... haha. Thanks for you help!
 
 
 
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