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    Could someone help with this question Thanks:

    The line joining (-3,-2) to(2e,5) has the gradient 2.Work out the value of e.
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    (Original post by iqra26)
    Could someone help with this question Thanks:

    The line joining (-3,-2) to(2e,5) has the gradient 2.Work out the value of e.
    use the equation
    (y-y1)=m(x-x1)
    y+2=2(x+3)
    y=2x+8

    substitute:
    5=2(2e)+8
    -3=4e
    e= -3/4
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    I'm not sure if this is right, but I'm sure someone will correct me if it's not. But I subbed the values into the formula to find the gradient (difference in y)/(difference in x)

    So I had (5--2)/(2e--3)=2 which I then simplified down to 7/2e+3=2. I then multiplied both sides by (2e+3) and then worked it out from there.
    So 7=4e+6
    1=4e
    e=1/4
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    (Original post by student004)
    use the equation
    (y-y1)=m(x-x1)
    y+2=2(x+3)
    y=2x+8

    substitute:
    5=2(2e)+8
    -3=4e
    e= -3/4
    Sorry I don't want to step on your toes but I think when you had y+2=2(x+3) you added 2 to both sides rather than subtracting. So it should be y=2x+4
    so 5=2(2e)+4
    1=4e
    e=1/4

    Sorry if you were right and I misread your working
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    (Original post by IfYouCanDreamIt)
    Sorry I don't want to step on your toes but I think when you had y+2=2(x+3) you added 2 to both sides rather than subtracting. So it should be y=2x+4
    so 5=2(2e)+4
    1=4e
    e=1/4

    Sorry if you were right and I misread your working
    No I think you are right, I did add 2 instead of subtracting.
    Thank you for pointing my mistake.
 
 
 
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