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    I got this question wrong and I don't understand the solution to the question. The solution seems to resolve the the component of tension acting on the toboggan and use this with the weight of the whole system to get the reaction force. Now what I don't get is why they have used the tension acting on the toboggan only and then use the weight of the whole system to work out the reaction on the toboggan. Shouldn't it be the weight of the toboggan only as the solution is using the vertical component of the tension on the toboggan only?
    Here's the question:
    Peter is pulling Paul, who is on a toboggan, along a rough horizontal snow surface using a rope which makes an angle of 30° with the horizontal. Paul and the toboggan have a total mass of 40 kg and the toboggan is moving in a straight line with constant speed. The rope is modelled as a light inextensible string. Given that the tension in the rope is 50 N, find the coefficient of friction between the toboggan and the snow.
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    Name:  Photo on 15-01-2017 at 18.55.jpg
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    This is my working, does that make sense?
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    (Original post by Darth_Narwhale)
    Name:  Photo on 15-01-2017 at 18.55.jpg
Views: 33
Size:  109.4 KB
    This is my working, does that make sense?
    Absolutely. The mistake I made was that I thought that the mass 40kg is of peter (from the beginning of the question) Paul and the toboggan. Thanks for your response.
 
 
 
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