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    Sup dudes and dudettes, I'm free for the next couple of hours so if you are stuck on any maths or physics questions/topic then hmu. I am currently doing physics at Cambridge and will try my best to help
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    (Original post by Darth_Narwhale)
    Sup dudes and dudettes, I'm free for the next couple of hours so if you are stuck on any maths or physics questions/topic then hmu. I am currently doing physics at Cambridge and will try my best to help
    If you want to help, just go around and answering unanswered threads. No-one will bother with a thread like this.
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    (Original post by Darth_Narwhale)
    Sup dudes and dudettes, I'm free for the next couple of hours so if you are stuck on any maths or physics questions/topic then hmu. I am currently doing physics at Cambridge and will try my best to help
    Please could you help me with this trig question?

    solve for 0 < x < 360 degrees

    2sin(x) = cos(x+60)

    This is what i've got so far....

    cos(x+60) = cosx cos60 - sinx sin60

    i just can't see where i have to go with it next....


    Thanks :-)
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    (Original post by ellie12344)
    Please could you help me with this trig question?

    solve for 0 < x < 360 degrees

    2sin(x) = cos(x+60)

    This is what i've got so far....

    cos(x+60) = cosx cos60 - sinx sin60

    i just can't see where i have to go with it next....


    Thanks :-)
    You know what cos (60) and sin(60) are, so you are left with an expression of sin(x) and cos(x). Get all the sin(x) terms on one side of the = and the cos(x) terms on the other side. Then divide by cos(x) to get something along the lines of tan(x) = ...

    Then just type it into the calculator. I got 9.9 and 189.9 but I may have made a mistake somewhere
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\int_{0}^{2\pi}\!\!\int_{0}^{\in  fty} e^{-r^2}r\,dr\,d\theta = \pi \
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    (Original post by Darth_Narwhale)
    You know what cos (60) and sin(60) are, so you are left with an expression of sin(x) and cos(x). Get all the sin(x) terms on one side of the = and the cos(x) terms on the other side. Then divide by cos(x) to get something along the lines of tan(x) = ...

    Then just type it into the calculator. I got 9.9 and 189.9 but I may have made a mistake somewhere


    Thank you very much!!!!
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    (Original post by Pikachū)
     

  

\int_{0}^{2\pi}\!\!\int_{0}^{\in  fty} e^{-r^2}r\,dr\,d\theta = \pi \

    What the hell is that O.o The only sign I know is the Integral, Change in (d) and Pi.

    Oh and the number 0.

    What does that formula do.....
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    (Original post by Pikachū)
     

  

\int_{0}^{2\pi}\!\!\int_{0}^{\in  fty} e^{-r^2}r\,dr\,d\theta = \pi \
    What on earth is the upper bound for the inner integrand?
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    (Original post by Bulletzone)
    What the hell is that O.o The only sign I know is the Integral, Change in (d) and Pi.

    Oh and the number 0.

    What does that formula do.....
    Grade 11 Japanese maths :yes:
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    (Original post by Pikachū)
    Grade 11 Japanese maths :yes:
    The hardest Year 11 maths i did was Quadratics :rofl:
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    (Original post by Pikachū)
    Grade 11 Japanese maths :yes:
    That's a gaussian integral in polar, but with an extra factor of r right? If the extra r wasn't there it would just be (pi)^1/2 I think...
 
 
 
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