Edexcel June 2012 M2 Watch

AlphaArgonian
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A bit of a weird question, but what are all the possible forces?

Haven't revised this in some time and have seemed to have completely forgotten how to label these diagrams (either that or my mind has blanked).
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(Original post by AlphaArgonian)
A bit of a weird question, but what are all the possible forces?

Haven't revised this in some time and have seemed to have completely forgotten how to label these diagrams (either that or my mind has blanked).
Name:  June2012M2Q3.PNG
Views: 65
Size:  48.4 KB
The forces acting on the rod will be the force F, the weight of the rod (5g) which will act vertically downwards at the centre of the rod (since the rod is uniform), plus you'll have a reaction force from the hinge.

A hinge reaction force acts to maintain equilbirum so it's not obvious which direction it acts. So it's best for hinges to draw on a vertical component (V) and a horizontal component (H) at the hinge.

So overall there should be four forces on your diagram : F, 5g, V and H.

To find F, you can take moments about the hinge. This will be useful since it won't include the forces V and H in your working so you can find F.
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