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    If any of you have the heinemann orange M1 book, could you please try and help me out with the following questions:

    Ex 2d: questions 9-12

    Ex 4A 3(a) once i can do this first one, im sure ill be able to do the rest of them.

    Thank you!
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    Just going out for a run now, plus I'm too lazy to type everything up...but for q3 of Ex 4A, the horizontal component of the forces added together is P + Rcos(theta), and the vertical component is Q + Rsin(theta). So for 3a), P = 3, Q = 4, R = 5 and theta = 60°, so the horizontal component is (3 + 2.5 = 5.5) and the vertical component is (4 + 2.5√3).

    The resultant magnitude is then √[5.5² + (4 + 2.5√3)²] = 9.982 N to 4SF, and the angle it makes with the x-axis is arctan(vertical/horizontal) = arctan[(4 + 2.5√3)/5.5] = 56.57° to 4SF.
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    (Original post by Squishy)
    sd
    ummm...its maybe coz im new here, but i have no idea what that stands for :confused:
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    Can you post the actual questions, I had to give mine back to my college a while ago but I'll probably be able to help. Just post the information you don't need to bother with the whole paragraph they use up to ask you a question.
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    (Original post by topdude)
    ummm...its maybe coz im new here, but i have no idea what that stands for :confused:
    Something went wrong with the post...sorry. I edited. Later.
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    (Original post by mik1a)
    Can you post the actual questions, I had to give mine back to my college a while ago but I'll probably be able to help. Just post the information you don't need to bother with the whole paragraph they use up to ask you a question.
    2D 9

    Particles position vector is 2i + j initially, and is accelating inot direction i + j. Magnitude is 5 root 2, find the velocity vector and speed after 2 seconds
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    (Original post by topdude)
    2D 9

    Particles position vector is 2i + j initially, and is accelating inot direction i + j. Magnitude is 5 root 2, find the velocity vector and speed after 2 seconds
    Acceleration vector: 5i + 5j. (It has to be parallel to i + j and have length 5 sqrt(2).)

    Velocity after 2 seconds (assuming we start at rest): 2*(5i + 5j) = 10i + 10j.

    Speed after 2 seconds: 2*(5 sqrt(2)) = 10 sqrt(2).
 
 
 
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Updated: August 7, 2004
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