A hollow copper tube is subjected to a tensile load. The tensile strength of the copper is 250MPa. If the tube has an outside diameter of 15mm and wall thickness of 0.7mm. Calculate the maximum value of the tensile force that can be applied to the tube if a factor of safety 3 is utilised
Can someone explain if what i'm doing is correct.
The outside diameter is 15mm and the thickness is 0.7mm
Is the area of hollow tube
pi*(15mm/2)^2 - pi(15-0.7mm/2)^2
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Area of hollow cylinder watch
- Thread Starter
Last edited by Super199; 17-01-2017 at 22:10.
- 17-01-2017 21:58
- 17-01-2017 22:54
That is correct (technically you should have written (15-7)/2 but hey